Яркие
80 грн/шт
Тусклые
70 грн/шт
Тёмные
75 грн/шт
SELECT * FROM Products as pd
join Oders as o on pd.ProductID = o.ProductID
where UserID = 1
Ім'я файлу: Документ Microsoft Word.docx Розширення: docx Розмір: 183кб. Дата: 25.04.2022 скачати Пов'язані файли: Курсова_управлінський_облік_Овчиннікова ОП-32.docx Перелік засобів навчання та обладнання навчального і загального вакцинація.docx історія хвороби.docx Інструкційна карта перевірка компресії.docx Інструкційна карта (1).docx Інструкційна карта (2).docx Реферат на тему_ _ Залізничний транспорт України_.docx 4.5. Родина Бобові.docx Програма корпор.docx Політичні режими.ppt реферат 1.doc ІНДЗ педагогіка.docx SELECT EmployeeID, LastName, FirstName FROM Employees where FirstName in ('Robert') SELECT EmployeeID, LastName, FirstName FROM Employees where FirstName = ('Robert') SELECT ProductID, ProductName, Price, Price/2 as Discount FROM [Products] where ProductID in ( '1', '3', '7', '9') SELECT ProductID, ProductName, Price, Price/2 as Discount FROM [Products] where ProductID in ( 1, 3, 7, 9) SELECT OrderID, CustomerID, EmployeeID, ShipperID FROM [Orders] where EmployeeID in ('5') OR CustomerID > 88 AND ShipperID in ('1') SELECT OrderID, CustomerID, EmployeeID, ShipperID FROM [Orders] where EmployeeID = (5) OR CustomerID > 88 AND ShipperID = (1) SELECT * FROM [Products] where ProductID >= 64 OR SupplierID in (SELECT SupplierID FROM [Suppliers] where SupplierName in ('Tokyo Traders')) SELECT * FROM [Products] where ProductID >= 64 OR SupplierID = (SELECT SupplierID FROM [Suppliers] where SupplierName = ('Tokyo Traders')) SELECT OrderID, LastName, FirstName FROM [Employees] join Orders on Employees.EmployeeID = Orders.EmployeeID SELECT * FROM [Employees] as e left join Orders as o on e.EmployeeID = o.EmployeeID where OrderID is null SELECT 'Orders' as TableName, ShipperName FROM [Shippers] union SELECT 'Suppliers', SupplierName FROM [Suppliers] SELECT Max(ProductID), LastName, FirstName FROM [Employees] as e join Products as p on e.EmployeeID = e.EmployeeID where LastName = ('Buchanan') AND FirstName = ('Steven') SELECT Max(OrderID), LastName, FirstName FROM [Employees] as e join Orders as o on e.EmployeeID = e.EmployeeID where LastName = 'Buchanan' AND FirstName = 'Steven' SELECT CategoryID, ProductName, Price FROM [Products] where Price > (SELECT Avg(Price) FROM [Products]) SELECT OrderID, Quantity*Price as Total FROM [OrderDetails] as o join Products as p on o.OrderDetailID = o.OrderDetailID Group by 1 INSERT INTO [Employees] VALUES (11, 'Gringo', 'Karl', '1990-11-05', 'EmpID11.pic', 'Steven Buchanan graduated from St. Andrews University, Scotland, with a BSC degree. He joined the company as a sales representative, was promoted to sales manager and was then named vice president of sales. Andrew is a member of the Sales Management Roundtable, the Seattle Chamber of Commerce, and the Pacific Rim Importers Association.') UPDATE [Employees] SET EmployeeID = 11 where EmployeeID = (SELECT CustomerID FROM [Customers] where CustomerID in (89, 90)) UPDATE [Oders] SET EmployeeID = 11 where CustomerID in (89, 90) Update [Products] Set Price = (SELECT Price*0.1 FROM [Products]) where Price = (SELECT Price FROM [Products] where Price > (SELECT Avg(Price) FROM [Products])) Update [Products] Set Price = Price*1.1 where Price > (SELECT Avg(Price) FROM [Products]) 7 - в болке HAVING 8 – DML ______ (все ответы правильные – не верно) 9 – Truncate ____________( SELECT – не верно)
Яркие 80 грн/шт Тусклые 70 грн/шт Тёмные 75 грн/шт SELECT * FROM Products as pd join Oders as o on pd.ProductID = o.ProductID where UserID = 1 |